Here are my formulas
1+sin(x)^2+3
- x^2+y^2+z^2
- sin^2\theta + cos^2\theta =1
- \frac{-b\pm\sqrt{b^2-4ac}}{2a}
- \int\limits_{a}^{b} x^2 dx$ inside text
- f(x) = \sum_{i=0}^{n} \frac{a_i}{1+x}
\boxed{x^2+y^2 = z^2}
\displaystyle \left({cf}\right)'=cf'